Maths Problems on Trains- Basic Concept

Problem on Trains is an another important topic of chapter Time Speed and Distance from competition point of view. First of all I would like to clear you the base concept of these problems. This chapter is one of the easiest chapters for students to solve with less calculations. These type of questions are  frequently asked in SSC, IBPS, Bank, RRB, bank clerical and other exams. Now lets read the concepts of Aptitude Problems on trains :-

Basic Rules

Concept 1^st :- The thickness of a person or length of moving object (examples bus, car, truck, etc.) is always neglected as compared to the length of the train.

Concept 2^nd :- If a train crosses a man, then the man will be considered as a point neglecting the location where the man is standing (either on platform or on road).

Moving Trains :

Concept 4th  : On passing a platform by a certain train the net distance travelled is the sum of length of train and the length of platform both. Concept 5th  : When a train passes through a pole or person standing, net distance travelled to pass is the length of the train Concept 6th  : When two trains are moving in opposite directions, then relative speed will be the addition of their individual speeds. Concept 7th  : When two trains are moving in same direction, then relative speed will be the subtraction of their individual speeds. Conversion of Units of speed How to convert speed in km/h into m/sec.?                1km/h →                                      We know that 1km. = 1000 metres                                                           1hour = 60 × 60 seconds                                        So, 1km/h = 1000/(60 × 60) m/sec.                                                                                On solving we get  1km/h = (5/18) m/sec.                                        1km/h = (5/18) m/sec. How to convert speed in m/sec into km/h.?                1m/sec →                                      We know that 1m. = 1/1000 km                                                        1second =1/( 60 × 60) hour                                        So, 1m/sec = (1/1000)/{1/(60 × 60)} km/hr.                                                                 = (1/1000) × (3600) km/hr.                                                                                On solving we get  1m/sec = (18/5) km/hr. 1m/sec = (18/5) km/hr. Hope you have enjoyed the base concept of this chapter till now. More Conceptual enjoyment with the Various Questions related to this chapter which are frequently asked in the examinations will be presented to your for self study on this blog soon, just keep visiting this blog regularly and writing me your related queries through comment or forum. Best of Luck for Exams. To be continued soon........................