Time and work Tricks for Competitive Exams Part -1

In the previous post of Time and work we discussed about some basic concepts of this chapter. Now we will see some of the various frequently asked important question of this chapter in competition like SSC, Bank (IBPS), and Railways. This chapter is one of the easiest chapters for students to solve with less calculations.

Type 1^st :- Fundamental formulae based Questions:-

In these type of questions you just have to read the questions carefully to analyse the given data in the question and then calculate the required answer with the help of formulae given in the last post of this blog.

Q1. 20 men can do a piece of work in 8 days. How many men are needed to complete the same work in 10 days?

Solution:- First of all you should read this question carefully and analyse it carefully in such manner:-

The work in this question is same means constant and only number of men and days are given for the first condition of completing the wok along with the number of days for the same work and number of men is required, So the formula for this type of question is :-

                                M₁ × D₁ = M₂ × D₂.

Data given :- M₁ = 20,  D₁ = 8, M₂ = ?, D₂. = 10

So as per our formula     20 × 8 = M₂ × 10

On calculating we get                M₂ = 16

Hence the required answer is 16 men.

Q2. 30 men working 7 hours a day can do a work in 18 days. In how many days will 21 men working 8 hours a day can do the same work?

Solution:- First of all you should read this question carefully and analyse it carefully in such manner:-

The work in this question is same means constant and number of men, days and number of hours per day are given for the first condition of completing the wok along with the number of men and number of hours per days for the same work and number of days is required, So the formula for this type of question is :-

         M₁ × D₁ × H₁  = M₂ × D₂ × H₂.

Data given :- M₁ = 30,  D₁ =18, H₁ = 7,  M₂ = 21, D₂. = ? H₂ = 8

So as per our formula     30 × 18 × 7 = 21 × D₂ × 8

 On calculating we get    D₂ = 22.5 days (22 and a half day.)

Hence the required answer is 22.5 days (22 and a half day.).

Q3. 20 women can prepare 40 articles in 24 days working 18 hours a day. Then in how many days can 36 women can prepare 48 articles working 16 hours a day?

Solution:- First of all you should read this question carefully and analyse it carefully in such manner:-

The work in this question is not same means its not constant and number of women, days, number of articles (work) and number of hours per day are given for the first condition of completing the work along with the number of women, number of articles (work) and number of hours per days for the same work and number of days is required, So the formula for this type of question is :-

 M₁ × D₁ × H₁  × W₂ = M₂ × D₂ × H₂ × W₁.

Data given :- M₁ = 20,  D₁ =24, H₁ = 18, W₁ = 40, M₂ = 36, D₂. = ?, H₂ = 16 & W₂ = 48

So as per our formula     20 × 24 × 18 × 48 = 36 × D₂ × 16 × 40

 On calculating we get                D₂ = 18 days.

               Hence the required answer is 18 days

Notes:- No need to write unnecessary steps, just avoid them as per your requirement. Just substitute the values in the formula direct and do the required calculations.

The Various more Questions related to this chapter which are frequently asked in the examinations will be presented to your for self study on this blog soon, so keep visiting and sending your suggestions and requirements too to us through the forum.