Maths Problems on Trains- Part -1

Problem on Trains is an another important topic of chapter Time Speed and Distance from competition point of view. In the previous post of Problem based on trains we have discussed about some basic concepts of this chapter. Now we will see some of the various frequently asked important question of this chapter in competition like SSC, Bank (IBPS), and Railways.

Important Types questions on Trains:-

Concept 1^st :-  Basic Questions on unit conversion:-

Q1. Convert speed of 90km/h into metres per second.

Sol. As we have seen in the previous post of this topic that 1km/h = (5/18) m/sec.

    Therefore 90km/h = 90 × (5/18) m/sec.

    On solving :-          = 25 m/sec.

Hence the required speed in metres per sec is 25m/sec.

Q2. Convert speed of 60m/sec. into kilometres per hour.

Sol. As we have seen in the previous post of this topic that 1m/sec. = (18/5) km/hr.

    Therefore 60m/sec = 60 × (18/5) km/hr.

    On solving :-          = 216 km/hr.

Hence the required speed in kilometres per hour is 216km/hr.

Concept 2^nd :- Train crossing stationary pole, Telegraph post or a stationary man:-

Q3. A train crosses a tree in 25 sec. If the length of the train is 375 meters, then find the speed of the train.

Note :- In this type of questions the only thing to be noticed is that all the dimensions should be same unit scale means either distance in kilometers and time in hours or distance in meters and time in seconds.

As we have discussed in the previous post of this topic that in such questions:-

the distance traveled by the train = length of the train

Formula used in such questions :-

                                     Speed of train = distance traveled/time taken to cross

Sol. Given Data :- Time taken to cross = 25 Sec.

and length of train = distance traveled by the train = 375 meters.

Now, speed of the train = Distance / time

                                        = 375/25 = 15 m/sec.

                                        = 15 × (18/5) km/hr.

                                        = 54 km/hr.

Hence the required speed of the train is 15 m/sec. or 54 km/hr. Note you may say that this is so long but dear this is the only way to explain the whole concept of the question to you now its upto you that how fast and short handedly you can solve these type of questions) Hope you have enjoyed the base concept of this chapter till now. More Conceptual enjoyment with the Various Questions related to this chapter which are frequently asked in the examinations will be presented to your for self study on this blog soon, just keep visiting this blog regularly and writing me your related queries through comment or forum. More types of questions will be followed soon on this blog........................ Best of Luck for Exams. To be continued soon........................