Here I am
presenting the first practice set of Trigonometry Questions on the special
demand of one of our sincere visitor, Mr. Anil Wagh. This practice set contains
20 Questions of the same pattern as we had discussed on this blog in our
previous post. I hope that you will be solve these questions, in case any
problem you may ask for help by sending the “solution required for question
no......” in comment or through forum.
Q1. If tanθ = 8/15 and θ is acute
angle, then find the value of Cosecθ.
Ans. 17/8
Q2. Evaluate the following:
3Cos2300
+ Sec2300 + 2Cos00 + 3Sin900 ─ tan2600
Ans. 67/12 or 5whole(7/12)
Q3. Sin600 Cos300
+ Cos600 Sin300 =?
Ans. 1
Q4. Evaluate the following:
Sin2600
+ Cos2300 + Cot2450 + Sec2600
─ Cosec2300
Ans. 5/2 .
Q5. 2Sin2300 ─ 3Cos2450
+ tan2600 = ?
Ans. 2.
Q6. Evaluate the following:
Sin2300
. Cos2450 + 4tan2300 + (1/2) Sin2900
─ 2Cos2900
Ans. (47/24)
Q7. If x tan450 . Cos600
= Sin600 . Cot600 then find the value of x
Ans. x = 1
Q8. If tan2450 ─
Cos2600 = x Sin450 . Cos450 tan600
, then find the value of x.
Ans. x = √3/2
Q9. If x Sin2600
─ (1/2) Sec600 . tan2300 + (4/3) Sin2450
. tan2600= 0, then find the value of x.
Ans. x = (─20/9)
Q10. If Sin420 = x then find
the value of Cos480
Ans. Cos480 = x
Q11. Sin2250 + Sin2650
= ?
Ans. 1.
Q12. Cos2750 + Cos2150
= ?
Ans. 1.
Q13. Sin2200 + Sin2700
─ tan2450 = ?
Ans. 0.
Q14. Sin200 Cos700
+ Cos200 Sin700 =?
Ans. 1.
Q15. Cos640 Cos260
─ Sin640 Sin260 =?
Ans. 0.
Q16. Sin530 Cos370
+ Cos530 Sin370 =?
Ans. 1.
Q17. Cos720 ─ Sin180
= ?
Ans. 0.
Q18. tan350 . tan400
. tan450 . tan500 . tan550 = ?
Ans. 1.
Q19. tan150 . tan250
. tan450 . tan650 . tan750 = ?
Ans. 1.
Q20. Find the value of Cos520
+ Cos680 + Cos1720 =?
Ans. 0.
Hope you have enjoyed these questions based this chapter
till now. Visitor’s are warm heartedly welcomed with their related problems and
queries. More Conceptual enjoyment will be continued for you soon, just keep
visiting this blog regularly and writing me your related queries through
comment or forum.
Best of Luck for Exams. To be continued soon........................
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