Here
I am presenting the solution of first practice set of Number System Questions.
Check your answers and clear your doubts:-
Q1. The set of counting numbers along
with zero is called the set of
(a)
Natural numbers (b)
Decimals (c) Whole numbers (d) None of these.
Sol.
As per definition and concept:-
The
set of counting numbers along with zero is called the set of Whole numbers
Option
(c)
Q2. The set of numbers {1, 2, 3,
4,.........} is called the set of
(a)
Whole numbers (b) Natural
numbers (c) Integers (d) None of these.
Sol.
As per definition and concept:-
The
set of numbers {1, 2, 3, 4,.........} is called the set of Natural numbers
Option
(b)
Q3. The number which is not a natural number but a whole number is
(a)
a fraction (b) 0 (c) a prime number (d) 1
Sol.
As per definition and concept:-
N
= {1, 2, 3, 4, ......... }
W
= {0, 1, 2, 3, 4, ......... }
The
number which is not a natural number
but a whole number is 0.
Option
(b)
Q4. The sum of successor and predecessor
of a whole number is equal to one more than the number. Then the number is
(a)
Any natural number (b) 1 (c) 2 (d) No such number
Sol.
Let the number be x.
Then
Successor = (x + 1) and Predecessor = (x - 1)
According
to the question (x + 1) + (x - 1) = (x + 1)
On
Solving we get x = 1.
Hence
the required number is 1.
Option
(b).
Q5. The sum of three odd natural numbers
multiplied by the sum of two even natural numbers is always
(a)
An even natural number (b) A
multiple of 9 (c) Odd natural number
(d)
None of these
Sol.
The sum of three odd natural numbers = odd natural number (example 3 + 5 + 7 =
15)
The
sum of two even natural numbers = Even natural numbers (example 4 + 6 = 10)
Now
The sum of three odd natural numbers × The sum of two even natural numbers
=
Odd natural number (15) × Even natural number (10)
=
Even natural number (150).
Hence
the sum of three odd natural numbers multiplied by the sum of two even natural
numbers is always an even natural number.
Option
(a)
Q6. Which of the following is always
odd?
(a)
Sum of two odd numbers (b) Product
of two odd numbers
(c) Difference of two odd numbers (d) Nine of these
Sol.
Odd number + Odd number = Even number.
Odd
number – Odd number = Even number.
Odd
number × Odd number = Odd number.
Hence
the product of two odd numbers is always odd number.
Option
(b)
Q7. The sum of first 100 natural
numbers is
(a)
10100 (b) 3750 (c) 5050 (d) 15050
Sol.
Number of terms in the series (n) = 100
Using
the formula, Sum of n- natural numbers = [{n (n + 1)}/2]
[{100
× (100 + 1)}/2]
On
solving we get 5050.
The
required sum = 5050.
Option
(c)
The rest solutions of the rest questions are followed in the next post soon............
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